MathematicsGrade 6–7

Percentage bar

Discounts, VAT, surveys: one single bar holds the base value, the percentage and the part, one above the other.

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What is it about?

Percent means hundredths: 1 %=11001\,\% = \frac{1}{100}, so 25 %=25100=14=0.2525\,\% = \frac{25}{100} = \frac14 = 0.25. Every percentage problem has three quantities:

  • the base value GG – the whole, it corresponds to 100 %100\,\% (purple),
  • the rate p %p\,\% (orange),
  • the percentage value WW – the part as a quantity, e.g. in euros (blue).

On the percentage bar, percentages are on top and values underneath. Rule of three on the bar (25 % of €80): split the bar into 100 equal parts, so 1 %  =^  €0.801\,\% \;\hat{=}\; €0.80, and 25 %  =^  25⋅€0.80=€2025\,\% \;\hat{=}\; 25 \cdot €0.80 = €20. To find the base value, go backwards: from the percentage value to 1 %1\,\% and then to 100 %100\,\%.

W=G⋅p100,p %=WG,G=W⋅100pW = G \cdot \frac{p}{100}, \qquad p\,\% = \frac{W}{G}, \qquad G = W \cdot \frac{100}{p}

With 20 % off you pay 80 %80\,\% of the old price (G⋅0.8G \cdot 0.8); after a 20 % rise it costs 120 %120\,\% (G⋅1.2G \cdot 1.2). German VAT is usually 19 %19\,\%, so the gross price is 119 %119\,\% of the net price. Pitfall: if a bike costs €84 after a 20 % rise, then €84  =^  120 %€84 \;\hat{=}\; 120\,\%, so it cost €84:1.2=€70€84 : 1.2 = €70 before – not €84−20 %=€67.20€84 - 20\,\% = €67.20.

Try it

  1. Start: press “Rule of three on the bar”. The bar splits into 100100 parts, then 2525 parts are counted. Watch the hundred square at the same time.
  2. Drag the orange handle, tap the bar or tap squares in the hundred square: set 10 %10\,\%, 25 %25\,\%, 50 %50\,\% and 75 %75\,\%. Which fractions belong to them? Three quarters as a circle
  3. 1 % of 250: why is 1 %1\,\% of 250250 equal to 2.52.5? What is 10 %10\,\% then?
  4. Find the base value: start the animation – now it counts backwards, from 15 %15\,\% via 1 %1\,\% to 100 %100\,\%.
  5. Above 100 %: the percentage value is larger than the base value. Where is the handle now?
  6. Everyday life: discount, price increase, receipt, savings, survey. Which part of the bar is the new price each time?
  7. Pitfall: compare the two bars. Why does the red bar end before the purple line?

Tasks

Task 1: Percentage value

What is 25 %25\,\% of €80? Load task

Show solution

100 %  =^  €80100\,\% \;\hat{=}\; €80, 1 %  =^  €0.801\,\% \;\hat{=}\; €0.80, 25 %  =^  25⋅€0.80=€2025\,\% \;\hat{=}\; 25 \cdot €0.80 = €20. Shorter: 25 %=1425\,\% = \frac14, and a quarter of €80 is €20. Show the solution

Task 2: In the sale

A jumper costs €60. There is 20 %20\,\% off. What does it cost now? Load task

Show solution

Discount: €60⋅0.2=€12€60 \cdot 0.2 = €12, new price €60−€12=€48€60 - €12 = €48. Shorter: you pay 80 %80\,\%, so €60⋅0.8=€48€60 \cdot 0.8 = €48. Show the solution

Task 3: The receipt

a) Headphones cost €50 before tax. What do they cost with 19 %19\,\% VAT? Load task

b) A receipt shows €119 including 19 %19\,\% VAT. What is the net price? Load task

Show solution

a) 19 %19\,\% of €50 is €9.50, together €59.50; shorter €50⋅1.19=€59.50€50 \cdot 1.19 = €59.50. Show

b) €119  =^  119 %€119 \;\hat{=}\; 119\,\%, so 1 %  =^  €11\,\% \;\hat{=}\; €1 and 100 %  =^  €100100\,\% \;\hat{=}\; €100. Show

Task 4: The savings account

There is €1200 in a savings account at an interest rate of 2.5 %2.5\,\% per year. How much interest is paid after one year, and what is the balance then? Load task

Show solution

1 %  =^  €121\,\% \;\hat{=}\; €12, so 2.5 %  =^  2.5⋅€12=€302.5\,\% \;\hat{=}\; 2.5 \cdot €12 = €30 interest. Balance: €1200+€30=€1230€1200 + €30 = €1230. Show the solution

Task 5: The pitfall

a) After a price rise of 20 %20\,\% a bike costs €84. What did it cost before? Load task

b) A price is first raised by 20 %20\,\% and then lowered by 20 %20\,\%. Is it back to where it started?

Show solution

a) €84  =^  120 %€84 \;\hat{=}\; 120\,\%, 1 %  =^  €0.701\,\% \;\hat{=}\; €0.70, 100 %  =^  €70100\,\% \;\hat{=}\; €70. Check: €70⋅1.2=€84€70 \cdot 1.2 = €84. Taking 20 %20\,\% of €84 off (€67.20) is wrong, because the 20 %20\,\% refer to the old price. Show

b) No: 1.2⋅0.8=0.961.2 \cdot 0.8 = 0.96. €100 becomes €120 and then €96 – in the end 4 %4\,\% less than at the start, because the decrease refers to the larger base value of €120.

Ideas for the classroom

  • With “Show the solution” switched off (show=0), the unknown appears as “?” – estimate on the bar first, then calculate and check with the animation. “New task” creates practice problems with friendly numbers.
  • Bar, hundred square and circle show the same share: a bridge from 34\frac34 via 0.750.75 to 75 %75\,\%.
  • Model: amounts of money are rounded to the cent; values that are not exact appear with “≈”. Interest for one year only, without compound interest.
  • Common stumbling blocks: mixing up base value and percentage value; confusing the discount or tax with the new price; subtracting the rate from the new value when working backwards (€84−20 %≠€70€84 - 20\,\% \ne €70); thinking that +20 % and −20 % cancel out; believing rates above 100 % are impossible; results such as 9.249.24 children – a good reason to talk about sensible answers.