You can see them as areas: a square with side length a+b consists of the square a2, the square b2 and two rectangles with area a⋅b. These two rectangles are exactly what is forgotten in the common mistake (a+b)2=a2+b2.
The formulas hold for all numbers – the areas are only an illustration for positive lengths (with a>b for the 2nd and 3rd formula).
Try it
Press Split apart and watch which parts the large square falls into. How many rectangles a⋅b are there?
Choose the second formula. Why do you have to addb2 again, even though something is being subtracted? 2nd formula
Choose the third formula and let the strip be moved. Which rectangle appears? 3rd formula
Change a and b and check the calculation with numbers under Results.
Exercises
Exercise 1: Clever mental arithmetic
Use a binomial formula to calculate in your head: 532, 492 and 21⋅19.
Show solution
532=(50+3)2=2500+300+9=2809
492=(50−1)2=2500−100+1=2401
21⋅19=(20+1)(20−1)=400−1=399
Exercise 2: Expanding
Expand: (x+4)2, (2x−3)2 and (5+y)(5−y).
Show solution
(x+4)2=x2+8x+16
(2x−3)2=4x2−12x+9 – careful: (2x)2=4x2 and 2⋅2x⋅3=12x.
(5+y)(5−y)=25−y2
Exercise 3: Find the mistake
Tom calculates (a+b)2=a2+b2. Check with a=5 and b=2 and use the simulation to explain what Tom forgot.
Show solution
(5+2)2=49, but 52+22=29. The missing 20=2⋅5⋅2 are the two rectanglesa⋅b. Show in the simulation
Exercise 4: Backwards – factorising
Write as a product: x2+10x+25, 49−y2 and 9a2−12ab+4b2.
Show solution
x2+10x+25=(x+5)2
49−y2=(7+y)(7−y)
9a2−12ab+4b2=(3a−2b)2
Ideas for the classroom
Use: About grade 7/8 (terms with brackets, binomial formulas). The area model works as an introduction and as a justification of why the middle term 2ab appears.
Animation: The button below the drawing area splits the figure apart or puts it back together. For the third formula a strip is rotated and moved – a visual justification of a2−b2.
Common stumbling blocks:
(a+b)2=a2+b2 (“the square is distributed over the terms”).
In (a−b)2 the +b2 feels wrong. The simulation shows that b2 is subtracted twice when the two strips are removed.
(2x)2=2x2 instead of 4x2.
Limits of the model: Areas need positive lengths, and for the 2nd and 3rd formula also a>b. If a≤b, the simulation shows no area model for these formulas, but the calculation with numbers under Results is still correct, e.g. (3−5)2=4=9−30+25. The formulas also hold for negative numbers – you can let students check this with numerical examples.