MathematicsGrade 7–9

Binomial formulas with squares

The three binomial formulas as areas: a square splits into smaller squares and rectangles.

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What is it about?

The three binomial formulas are shortcuts for expanding brackets:

(a+b)2=a2+2ab+b2(a−b)2=a2−2ab+b2(a+b)(a−b)=a2−b2\begin{aligned} (a + b)^2 &= a^2 + 2ab + b^2 \\ (a - b)^2 &= a^2 - 2ab + b^2 \\ (a + b)(a - b) &= a^2 - b^2 \end{aligned}

You can see them as areas: a square with side length a+ba + b consists of the square a2a^2, the square b2b^2 and two rectangles with area a⋅ba \cdot b. These two rectangles are exactly what is forgotten in the common mistake (a+b)2=a2+b2(a + b)^2 = a^2 + b^2.

The formulas hold for all numbers – the areas are only an illustration for positive lengths (with a>ba > b for the 2nd and 3rd formula).

Try it

  1. Press Split apart and watch which parts the large square falls into. How many rectangles a⋅ba \cdot b are there?
  2. Choose the second formula. Why do you have to add b2b^2 again, even though something is being subtracted? 2nd formula
  3. Choose the third formula and let the strip be moved. Which rectangle appears? 3rd formula
  4. Change aa and bb and check the calculation with numbers under Results.

Exercises

Exercise 1: Clever mental arithmetic

Use a binomial formula to calculate in your head: 53253^2, 49249^2 and 21⋅1921 \cdot 19.

Show solution
  • 532=(50+3)2=2500+300+9=280953^2 = (50 + 3)^2 = 2500 + 300 + 9 = 2809
  • 492=(50−1)2=2500−100+1=240149^2 = (50 - 1)^2 = 2500 - 100 + 1 = 2401
  • 21⋅19=(20+1)(20−1)=400−1=39921 \cdot 19 = (20 + 1)(20 - 1) = 400 - 1 = 399

Exercise 2: Expanding

Expand: (x+4)2(x + 4)^2, (2x−3)2(2x - 3)^2 and (5+y)(5−y)(5 + y)(5 - y).

Show solution
  • (x+4)2=x2+8x+16(x + 4)^2 = x^2 + 8x + 16
  • (2x−3)2=4x2−12x+9(2x - 3)^2 = 4x^2 - 12x + 9 – careful: (2x)2=4x2(2x)^2 = 4x^2 and 2⋅2x⋅3=12x2 \cdot 2x \cdot 3 = 12x.
  • (5+y)(5−y)=25−y2(5 + y)(5 - y) = 25 - y^2

Exercise 3: Find the mistake

Tom calculates (a+b)2=a2+b2(a + b)^2 = a^2 + b^2. Check with a=5a = 5 and b=2b = 2 and use the simulation to explain what Tom forgot.

Show solution

(5+2)2=49(5 + 2)^2 = 49, but 52+22=295^2 + 2^2 = 29. The missing 20=2⋅5⋅220 = 2 \cdot 5 \cdot 2 are the two rectangles a⋅ba \cdot b. Show in the simulation

Exercise 4: Backwards – factorising

Write as a product: x2+10x+25x^2 + 10x + 25, 49−y249 - y^2 and 9a2−12ab+4b29a^2 - 12ab + 4b^2.

Show solution
  • x2+10x+25=(x+5)2x^2 + 10x + 25 = (x + 5)^2
  • 49−y2=(7+y)(7−y)49 - y^2 = (7 + y)(7 - y)
  • 9a2−12ab+4b2=(3a−2b)29a^2 - 12ab + 4b^2 = (3a - 2b)^2

Ideas for the classroom

  • Use: About grade 7/8 (terms with brackets, binomial formulas). The area model works as an introduction and as a justification of why the middle term 2ab2ab appears.
  • Animation: The button below the drawing area splits the figure apart or puts it back together. For the third formula a strip is rotated and moved – a visual justification of a2−b2a^2 - b^2.
  • Common stumbling blocks:
    • (a+b)2=a2+b2(a + b)^2 = a^2 + b^2 (“the square is distributed over the terms”).
    • In (a−b)2(a - b)^2 the +b2+b^2 feels wrong. The simulation shows that b2b^2 is subtracted twice when the two strips are removed.
    • (2x)2=2x2(2x)^2 = 2x^2 instead of 4x24x^2.
  • Limits of the model: Areas need positive lengths, and for the 2nd and 3rd formula also a>ba > b. If a≤ba \le b, the simulation shows no area model for these formulas, but the calculation with numbers under Results is still correct, e.g. (3−5)2=4=9−30+25(3 - 5)^2 = 4 = 9 - 30 + 25. The formulas also hold for negative numbers – you can let students check this with numerical examples.