MathematicsGrade 6–8

Direct and inverse proportion

Twice as many apples cost twice as much. Picture, table and graph show together when a relation is proportional, with the rule of three.

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What is it about?

In a relation (or assignment) each xx value goes with exactly one yy value. Two special relations come up all the time in everyday life. In the simulation every quantity has its own colour: xx blue, yy purple, the constant kk orange.

Directly proportional – “twice as much, twice the price”: doubling (tripling, …) xx doubles (triples, …) yy. All quotients are equal (constant quotient):

yx=ksoy=k⋅x\frac{y}{x} = k \qquad\text{so}\qquad y = k \cdot x

kk is called the constant of proportionality. The graph is a ray through the origin; the slope triangles “1 to the right, kk up” have the same shape everywhere.

Inversely proportional – “twice as many, half the time”: doubling xx halves yy, tripling xx gives a third of yy. All products are equal (constant product):

x⋅y=ksoy=kxx \cdot y = k \qquad\text{so}\qquad y = \frac{k}{x}

The graph is a branch of a hyperbola. All rectangles under its points have area kk – they become narrower and taller or wider and flatter, but never bigger or smaller.

The rule of three uses exactly these properties: first work out one unit, then the wanted amount. Examples: apples (4 kg4\,\text{kg} cost €10€10) and a pool that 66 pumps fill in 10 h10\,\text{h}.

directly proportional inversely proportional
known 4 kg  =^  €104\,\text{kg} \;\hat{=}\; €10 6 pumps  =^  10 h6\ \text{pumps} \;\hat{=}\; 10\,\text{h}
one unit 1 kg  =^  €2.501\,\text{kg} \;\hat{=}\; €2.50 (both sides :4: 4) 1 pump  =^  60 h1\ \text{pump} \;\hat{=}\; 60\,\text{h} (left :6: 6, right ⋅6\cdot 6)
wanted 7 kg  =^  €17.507\,\text{kg} \;\hat{=}\; €17.50 (both sides ⋅7\cdot 7) 4 pumps  =^  15 h4\ \text{pumps} \;\hat{=}\; 15\,\text{h} (left ⋅4\cdot 4, right :4: 4)
memory aid same direction opposite direction

Careful, trap: not every “the more – the more” relation is proportional. A taxi costs a base fare of €3€3 plus €2€2 per km. 5 km5\,\text{km} cost €13€13, but 10 km10\,\text{km} cost only €23€23 – not €26€26. The quotients 13:5=2.613 : 5 = 2.6 and 23:10=2.323 : 10 = 2.3 differ, and the line y=2x+3y = 2x + 3 does not pass through the origin.

How to check a table of values: work out the quotients y:xy : x – all equal? Then directly proportional. Otherwise work out the products x⋅yx \cdot y – all equal? Then inversely proportional. Otherwise neither.

Try it

  1. Apples on the scales: drag PP along the graph or tap a column of the table. What always stays the same in the row y:xy : x? Compare the small orange triangles.
  2. Press “Double it”: the mass is doubled. What happens to the price on the scales, in the table (arrows below) and in the graph?
  3. Pumps at the pool: press “Double it”. How fast does the pool fill now? Then drag PP and watch the rectangle: which number never changes?
  4. Six pumps, ten hours: run “Rule of three step by step”. Why is there “⋅6\cdot 6” on the right when there is “:6: 6” on the left?
  5. Taxi trap: press “Double it”. Where is the point “€26?” and where is the real fare? What do the dashed rays from the origin show?
  6. Test: sharing pizza: tap your guess first, then “Check the table”. “Next table” takes you on – including two traps.

Tasks

Task 1: Buying apples

4 kg4\,\text{kg} of apples cost €10€10. How much do 7 kg7\,\text{kg} cost? Load task

Show solution

4 kg  =^  €10  →:4  1 kg  =^  €2.50  →⋅7  7 kg  =^  €17.504\,\text{kg} \;\hat{=}\; €10 \;\xrightarrow{:4}\; 1\,\text{kg} \;\hat{=}\; €2.50 \;\xrightarrow{\cdot 7}\; 7\,\text{kg} \;\hat{=}\; €17.50. Check: 17.50:7=2.5=10:417.50 : 7 = 2.5 = 10 : 4. Show the solution

Task 2: Pumps at the pool

66 pumps of equal power fill a pool in 1010 hours. How long do 44 pumps take, how long do 55 pumps take? Load task

Show solution

One pump takes 6⋅10 h=60 h6 \cdot 10\,\text{h} = 60\,\text{h}. Four pumps take 60 h:4=15 h60\,\text{h} : 4 = 15\,\text{h}, five pumps 60 h:5=12 h60\,\text{h} : 5 = 12\,\text{h}. Check: 6⋅10=4⋅15=5⋅12=606 \cdot 10 = 4 \cdot 15 = 5 \cdot 12 = 60. Show the solution

Task 3: Doubling and tripling

33 pumps fill a pool in 44 hours. How long do 66 pumps take, how long do 99 pumps take? Give the second answer in hours and minutes. Load task

Show solution

Twice as many pumps need half the time: 4 h:2=2 h4\,\text{h} : 2 = 2\,\text{h}. Three times as many pumps need a third: 4 h:3=113 h=1 h  20 min4\,\text{h} : 3 = 1\tfrac{1}{3}\,\text{h} = 1\,\text{h}\;20\,\text{min}. Show the solution

Task 4: Lisa and the taxi

A taxi costs a base fare of €3€3 plus €2€2 per km. Lisa says: “5 km5\,\text{km} cost €13€13, so 10 km10\,\text{km} cost twice as much, that is €26€26.” Is she right? Load task

Show solution

No. 10 km10\,\text{km} cost €3+10⋅€2=€23€3 + 10 \cdot €2 = €23. The base fare is paid only once, so the fare is not proportional to the distance. The quotients show it too: 13:5=2.613 : 5 = 2.6, but 23:10=2.323 : 10 = 2.3. Show the solution

Task 5: Check three tables

Which table belongs to a directly proportional relation, which to an inversely proportional one, and which to neither? For the proportional ones, give the value of kk.

(a) (1∣3), (2∣6), (5∣15)(1 \mid 3),\ (2 \mid 6),\ (5 \mid 15) (b) (2∣12), (3∣8), (6∣4)(2 \mid 12),\ (3 \mid 8),\ (6 \mid 4) (c) (1∣5), (2∣7), (3∣9)(1 \mid 5),\ (2 \mid 7),\ (3 \mid 9)

Load task

Show solution

(a) Quotients 3:1=6:2=15:5=33 : 1 = 6 : 2 = 15 : 5 = 3: directly proportional, y=3xy = 3x. (b) Products 2⋅12=3⋅8=6⋅4=242 \cdot 12 = 3 \cdot 8 = 6 \cdot 4 = 24: inversely proportional, y=24xy = \frac{24}{x}. (c) Quotients 5, 3.5, 35,\ 3.5,\ 3 and products 5, 14, 275,\ 14,\ 27 – neither (y=2x+3y = 2x + 3, like the taxi). Show (a) · Show (b) · Show (c)

Task 6: Getting there faster

For a distance of 120 km120\,\text{km} you need exactly 3 h3\,\text{h} at 40 kmh40\,\tfrac{\text{km}}{\text{h}}. Explain why speed and travel time are inversely proportional, and work out the travel time at 50 kmh50\,\tfrac{\text{km}}{\text{h}} and at 90 kmh90\,\tfrac{\text{km}}{\text{h}}. Load task

Show solution

The distance stays the same: speed times travel time is always 120 km120\,\text{km}, so v⋅t=120v \cdot t = 120 (constant product). At 50 kmh50\,\tfrac{\text{km}}{\text{h}}: t=120:50=2.4 h=2 h  24 mint = 120 : 50 = 2.4\,\text{h} = 2\,\text{h}\;24\,\text{min}. At 90 kmh90\,\tfrac{\text{km}}{\text{h}}: t=120:90=113 h=1 h  20 mint = 120 : 90 = 1\tfrac{1}{3}\,\text{h} = 1\,\text{h}\;20\,\text{min}. Show

Ideas for the classroom

  • Use: proportional and inversely proportional relations with the rule of three (grade 6 or 7, depending on school type and federal state) and their return with linear functions (direct proportion) and hyperbolas (inverse proportion).
  • Three representations: picture, table and graph react together. It can pay off to cover one of them and let students predict what “Double it” will do there.
  • Tasks from the picture: with “Show the solution” off (show=0) unknown values appear as “?”. In the test, students can tap a guess first and then check it; “Next table” works well for a short round with the whole class.
  • Sorting task: students collect everyday examples (fuel price, workers and working time, age and shoe size, phone contract with a base fee …) and sort them into the three cases before checking.
  • Model: for the pumps only whole numbers make sense; the branch of the hyperbola connects the meaningful points. The age and height values are approximate averages.
  • Common stumbling blocks:
    • “The more – the more” is taken to mean directly proportional (taxi, age and height).
    • In the inverse rule of three the right side is treated the same way as the left – the memory aid “opposite direction” helps here.
    • The graph of an inverse proportion is drawn as a falling straight line; the products show that this does not fit.
    • Only one quotient is worked out. To decide, you need all pairs of the table.