PhysicsGrade 9–11

Free fall

A ball falls on Earth, the Moon or Mars and gets faster every second. In a vacuum even a feather keeps up.

Loading simulation …

What is it about?

When you let go of an object, it falls faster and faster. Without air resistance, free fall is a uniformly accelerated motion with the gravitational acceleration gg. In Central Europe g≈9.81 ms2g \approx 9.81\,\tfrac{\text{m}}{\text{s}^2}. Starting from rest, the laws of free fall are

s=12 g t2v=g⋅t.s = \tfrac{1}{2}\, g\, t^2 \qquad v = g \cdot t .

For a drop height hh this gives the fall time and the impact speed

t=2hgv=2 g h.t = \sqrt{\frac{2h}{g}} \qquad v = \sqrt{2\, g\, h}.

Converting to km/h: An hour has 3600 s3600\,\text{s} and a kilometre 1000 m1000\,\text{m}. So 1 ms=3.6 kmh1\,\tfrac{\text{m}}{\text{s}} = 3.6\,\tfrac{\text{km}}{\text{h}}: multiply by 3.63.6.

Stroboscope: If a lamp flashes at equal time intervals Δt\Delta t, you see the ball at several positions. The gaps grow in the ratio 1:3:5:7:…1 : 3 : 5 : 7 : \ldots – each gap is g⋅(Δt)2g \cdot (\Delta t)^2 larger than the one before.

Mass does not matter: Without air, a heavy ball and a light feather fall equally fast. In air, air resistance slows the feather down strongly: it soon reaches a small terminal velocity and then falls almost uniformly. On the Moon (no air), an astronaut of the Apollo 15 mission dropped a hammer and a feather in 1971 – both reached the ground at the same time.

Other celestial bodies have different values of gg: Moon 1.62 ms21.62\,\tfrac{\text{m}}{\text{s}^2}, Mars 3.71 ms23.71\,\tfrac{\text{m}}{\text{s}^2}, Jupiter 24.79 ms224.79\,\tfrac{\text{m}}{\text{s}^2}.

Reaction time: If you catch a falling ruler, the distance ss it fell gives your reaction time: t=2sgt = \sqrt{\frac{2s}{g}}.

Try it

  1. Press Drop and look at the stroboscopic picture. Read the gaps on the blue bar: 1:3:5:7:91 : 3 : 5 : 7 : 9.
  2. Drag the ball in the drop tower (or the point in the distance–time graph) and watch how time and speed change. The triangle in the velocity–time graph shows the slope gg, the area under the line shows the distance fallen.
  3. Repeat the experiment on the Moon and on Jupiter. On the Moon
  4. Turn the feather tube over – once with air, once in a vacuum. Tube with air · Tube in a vacuum
  5. Measure your reaction time: press Start and catch the ruler (tap, click or space bar). Do at least five attempts. Reaction test

Tasks

Task 1: Drop tower

Load task

A ball falls from a height of 20 m20\,\text{m} (no air resistance). How long does the fall take, and how fast is the ball at the bottom?

Show solution

t=2⋅20 m9.81 m/s2≈2.02 st = \sqrt{\frac{2 \cdot 20\,\text{m}}{9.81\,\text{m/s}^2}} \approx 2.02\,\text{s} and v=g⋅t≈19.8 ms≈71 kmhv = g \cdot t \approx 19.8\,\tfrac{\text{m}}{\text{s}} \approx 71\,\tfrac{\text{km}}{\text{h}}.

Task 2: Analysing a stroboscopic picture

Load task

The stroboscope flashes every 0.4 s0.4\,\text{s}. Calculate the gaps between the first five images and their ratio.

Show solution

Positions: s(0.4 s)≈0.78 ms(0.4\,\text{s}) \approx 0.78\,\text{m}, s(0.8 s)≈3.14 ms(0.8\,\text{s}) \approx 3.14\,\text{m}, s(1.2 s)≈7.06 ms(1.2\,\text{s}) \approx 7.06\,\text{m}, s(1.6 s)≈12.56 ms(1.6\,\text{s}) \approx 12.56\,\text{m}. Gaps: 0.78 m0.78\,\text{m}; 2.35 m2.35\,\text{m}; 3.92 m3.92\,\text{m}; 5.49 m5.49\,\text{m} – so 1:3:5:71 : 3 : 5 : 7. Each gap is g⋅(0.4 s)2≈1.57 mg \cdot (0.4\,\text{s})^2 \approx 1.57\,\text{m} larger than the one before.

Task 3: On the Moon

Load task

How long does the ball take to fall 20 m20\,\text{m} on the Moon? How many times longer is that than on Earth?

Show solution

t=2⋅201.62 s≈4.97 st = \sqrt{\frac{2 \cdot 20}{1.62}}\,\text{s} \approx 4.97\,\text{s} – about 9.81/1.62≈2.5\sqrt{9.81 / 1.62} \approx 2.5 times as long as on Earth.

Task 4: Depth of a well

A stone falls into a well and hits the water after 2 s2\,\text{s}. How deep is the well (ignore air resistance and the travel time of the sound)?

Show solution

s=12⋅9.81 ms2⋅(2 s)2≈19.6 ms = \tfrac12 \cdot 9.81\,\tfrac{\text{m}}{\text{s}^2} \cdot (2\,\text{s})^2 \approx 19.6\,\text{m}. Check in the simulation (nearest slider value 19.5 m19.5\,\text{m}, fall time 1.99 s1.99\,\text{s})

Task 5: Reaction time and reaction distance

Someone catches the ruler after 18 cm18\,\text{cm}. What is the reaction time? How far does a car travelling at 50 kmh50\,\tfrac{\text{km}}{\text{h}} move in this time before the driver even starts to brake?

Show solution

t=2⋅0.18 m9.81 m/s2≈0.19 st = \sqrt{\frac{2 \cdot 0.18\,\text{m}}{9.81\,\text{m/s}^2}} \approx 0.19\,\text{s}. With 50 kmh≈13.9 ms50\,\tfrac{\text{km}}{\text{h}} \approx 13.9\,\tfrac{\text{m}}{\text{s}} the reaction distance is about 13.9 ms⋅0.192 s≈2.7 m13.9\,\tfrac{\text{m}}{\text{s}} \cdot 0.192\,\text{s} \approx 2.7\,\text{m}. In traffic, about 1 s1\,\text{s} of reaction time is assumed, because you first have to notice the danger and move your foot.

Task 6: Feather and ball

Explain why the feather takes much longer in the tube with air, but falls just as fast as the ball in the evacuated tube. With air · Vacuum

Show solution

The weight acts on both; without air, both accelerate with gg – regardless of their mass. In air, air resistance acts as well. It grows with the speed, and for the light feather with its large surface it equals the feather’s weight at only about 0.6 ms0.6\,\tfrac{\text{m}}{\text{s}} – after that the feather does not get any faster. For the heavy, small ball it hardly matters over 1.5 m1.5\,\text{m}.

Task 7: Apple from a tree

Load task

An apple falls from a tree at a height of 5 m5\,\text{m}. How fast is it when it hits the ground? Give the speed in ms\tfrac{\text{m}}{\text{s}} and in kmh\tfrac{\text{km}}{\text{h}}.

Show solution

v=2⋅9.81 ms2⋅5 m=98.1 ms≈9.9 msv = \sqrt{2 \cdot 9.81\,\tfrac{\text{m}}{\text{s}^2} \cdot 5\,\text{m}} = \sqrt{98.1}\,\tfrac{\text{m}}{\text{s}} \approx 9.9\,\tfrac{\text{m}}{\text{s}}. Times 3.63.6: 9.9⋅3.6≈36 kmh9.9 \cdot 3.6 \approx 36\,\tfrac{\text{km}}{\text{h}}.

Ideas for the classroom

  • Use: Uniformly accelerated motion and the laws of free fall (grades 9/10), historical link to Galileo, application in traffic (reaction time). Each of the three experiments can be opened directly with a link containing mode=….
  • Model: The drop tower ignores air resistance. In the tube, air resistance is modelled as proportional to v2v^2, with terminal velocities of about 75 ms75\,\tfrac{\text{m}}{\text{s}} (steel ball, diameter 3 cm3\,\text{cm}) and 0.6 ms0.6\,\tfrac{\text{m}}{\text{s}} (feather) – these are approximate values. The swaying of the feather is only hinted at. Jupiter has no solid surface; the value 24.79 ms224.79\,\tfrac{\text{m}}{\text{s}^2} applies at the height of the cloud tops – the drop tower there is a thought experiment.
  • Reaction test: The ruler falls after a random waiting time (1.2 to 3.5 s). Screen and input devices add a delay of a few hundredths of a second, so the measured times are usually a little longer than with a real ruler. Comparing with a real ruler (pair work) is a good idea – with the ms scale switched on, the ruler becomes a “reaction time ruler”.
  • Common stumbling blocks:
    • “Heavy objects fall faster.” – Only air resistance makes a difference.
    • “In equal times the object falls equal distances.” – The gaps in the stroboscopic picture keep growing, each time by the same amount g⋅(Δt)2g \cdot (\Delta t)^2.
    • “There is no gravity on the Moon.” – It is only about one sixth as strong.
    • “gg is a speed.” – gg tells you by how many ms\tfrac{\text{m}}{\text{s}} the speed increases every second.