MathematicsGrade 11–13 · University

Integral function and fundamental theorem

The area under a graph grows as you move along. Its rate of change is exactly the function itself: this is the fundamental theorem.

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What is it about?

The integral function Ia(x)=∫axf(t) dtI_a(x) = \int_a^x f(t)\,dt measures the signed area from aa to xx (green above, red below the xx-axis); always Ia(a)=0I_a(a) = 0.

Fundamental theorem (for continuous ff): Ia′(x)=f(x)I_a'(x) = f(x) – the mean height Ia(x+h)−Ia(x)h\frac{I_a(x+h) - I_a(x)}{h} of a strip lies between min⁡f\min f and max⁡f\max f on the strip and tends to f(x)f(x) as h→0h \to 0. For every antiderivative FF: ∫abf(x) dx=F(b)−F(a)\int_a^b f(x)\,dx = F(b) - F(a); a constant CC cancels.

Consequences: zeros of ff with a sign change are extrema of IaI_a, extrema of ff are points of inflection of IaI_a, and another lower limit only shifts the graph vertically. Integrating a rate of change gives the total change: speed → distance, power → energy, marginal cost → cost …

Try it

  1. Parabola: press “Let the area grow”.
  2. Strip h → 0: press “Let h tend to 0” and watch the secant.
  3. Working: change the constant CC – the result stays the same.
  4. Cubic: find maxima, minima and inflection points of I−3I_{-3}; then move aa.
  5. Applications: car, solar panels, medicine, thunderstorm.

Tasks

Task 1: Evaluate

Evaluate ∫−12(0.5x2−1) dx\int_{-1}^{2}(0.5x^2 - 1)\,dx. Load task

Show solution

F(x)=16x3−xF(x) = \frac16 x^3 - x, so F(2)−F(−1)=−23−56=−1.5F(2) - F(-1) = -\frac23 - \frac56 = -1.5. Show

Task 2: How far does the car travel?

Speed 3t3t for 5 s, then 15 s at 15 ms15\,\tfrac{\text{m}}{\text{s}}, then 5 s of even braking. Load task

Show solution

37.5 m+225 m+37.5 m=300 m37.5\,\text{m} + 225\,\text{m} + 37.5\,\text{m} = 300\,\text{m}. Show

Task 3: Riemann sums

For f(x)=x2f(x) = x^2 on [0,2][0, 2] with n=4n = 4: left, right, midpoint and trapezoid sums? Load task

Show solution

1.751.75, 3.753.75, 2.6252.625 and 2.752.75; exact value 83≈2.667\frac83 \approx 2.667. Show

Ideas for the classroom

  • The views follow a possible lesson sequence: integral function → derivative (idea of proof) → evaluation → curve sketching of IaI_a → Riemann sums. The applications connect integrals with units (kW · h = kWh).
  • Common stumbling blocks: confusing the integral with the area when ff changes sign; equating integral functions with all antiderivatives; swapping F(b)−F(a)F(b) - F(a); forgetting that the theorem needs continuity (at a jump II has a kink).