What is it about?
Light falling on a metal can release electrons: the photoelectric effect. Below a threshold frequency no electrons are released, however bright the light. More intensity gives more electrons, but not faster ones. Einstein explained this with photons of energy EPh=h⋅f. One photon gives its energy to one electron, which needs the work function WA to leave the metal:
Ekin,max=h⋅f−WA.
With a retarding voltage U between anode and cathode the current vanishes at e⋅UG=Ekin,max. Plotting e⋅UG against f gives Einstein’s line with slope h≈4.14⋅10−15eV⋅s and threshold frequency fG=hWA.
Work functions (rounded textbook values): caesium 1.94eV, potassium 2.25eV, sodium 2.28eV, lithium 2.46eV, zinc 4.34eV, copper 4.48eV.
Try it
- Watch the electrons at U=0, then increase the retarding voltage. Load example
- Press “Adjust the voltage”. No current
- Double the intensity from 50% to 100%: the current doubles, UG stays. 50 % · 100 %
- Try red light. Red light
- Record an automatic series and read off the slope.
Tasks
Task 1: Violet light on caesium
λ=400nm, WA=1.94eV. Find EPh, Ekin,max and UG. Load task
Show solution
EPh=400nm1240eV⋅nm≈3.10eV, Ekin,max=1.16eV, UG=1.16V. Show in the simulation
Task 2: Threshold frequency
Find fG for caesium. Does red light (650nm) release electrons?
Show solution
fG=4.136⋅10−15eV⋅s1.94eV≈4.69⋅1014Hz (λG≈639nm). At 650nm, EPh≈1.91eV<WA: no electrons. Show in the simulation
Task 3: Zinc
Why does 400nm light release no electrons from zinc (WA=4.34eV)?
Show solution
3.10eV<4.34eV; zinc needs λ<286nm (UV). Show in the simulation
Ideas for the classroom
- Collect the three surprising observations first, then compare with the wave model.
- Common stumbling blocks:
- “Brighter light makes faster electrons.” – More light means more photons, not more energetic ones.
- “Ekin=h⋅f.” – The work function is missing.